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60=-7t+4.9t^2
We move all terms to the left:
60-(-7t+4.9t^2)=0
We get rid of parentheses
-4.9t^2+7t+60=0
a = -4.9; b = 7; c = +60;
Δ = b2-4ac
Δ = 72-4·(-4.9)·60
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-35}{2*-4.9}=\frac{-42}{-9.8} =4+2.8/9.8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+35}{2*-4.9}=\frac{28}{-9.8} =-2+6/7 $
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